Guwahati:Sunrisers Hyderabad (SRH) won the toss, and elects to bat first against Kings XI Punjab (KXIP).
Sunrisers Hyderabad (SRH) face Kings XI Punjab (KXIP) in Match 22 of the Dream11 Indian Premier League (IPL) 2020 and both teams will be eyeing a winning return at the Dubai International Cricket Stadium on Thursday.
SRH and KXIP have four and two points each against their name from 5 matches. While SRH lost their first two games of the season against Royal Challengers Bangalore (RCB) and Kolkata Knight Riders (KKR), they bounced back and won two games in a row, beating Delhi Capitals (DC) and Chennai Super Kings (CSK). However, the David Warner-led side could not complete a hat-trick of wins following their defeat against Mumbai Indians (MI).
Coming to KXIP, they will be seeking to break the three-match losing streak. While KXIP ended on the losing side following a Super Over-thriller in their first game against DC, they defeated RCB in their second game of the season. However, KL Rahul and Co. lost three games in a row against Rajasthan Royals (RR), MI and CSK.
